Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 70 3 b Solution Created 2026-10-03 Updated 2026-10-14
Outside the thin burning shell, the enclosed mass and luminosity are approximately and . Divide the hydrostatic pressure support equation by radiative diffusion in a star with constant opacity:In the constant-opacity radiative-zero giant envelope approximation, the outer pressure and temperature constants are negligible. Integration givesThe radiation pressure is , so the gas pressure fraction is constant and satisfies . Thus alsoThe physical branch has positive gas pressure, hence , the constant-opacity Eddington luminosity for the core mass.
Using the gas part of the equation of state, define , so . Substitution into hydrostatic balance givesConsequently, in the same deep-envelope radiative-zero approximation,Precisely, a finite outer matching point gives . The displayed profile neglects that additive outer-boundary constant; it is appropriate near a compact core when the envelope extends to much smaller temperatures.
To estimate the thin-shell luminosity, write , so . The hydrogen-layer heating law givesThis steep radial dependence strongly concentrates the emission near . Continuing the outer profile across the thin emitting layer and taking a distant upper limit givesThe same radiative coefficient implies . Hence the high-power shell burning in a constant-opacity giant envelope satisfiesTaking the cube root gives the requested form,Thus contains only the specified opacity and heating normalizations and physical constants. The explicit coefficient uses the outer radiative profile as a thin-shell estimate; resolving the variation of within the emitting layer can change that coefficient. Also depends on , so the radiation-pressure-inclusive relation is implicit, not a pure explicit eighth-power core-mass law with independently fixed .