Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 118 5 c Solution Created 2026-10-03 Updated 2026-10-05
For degree zero, compactness and the maximum modulus principle make holomorphic functions constant on each connected component. For degree two, a holomorphic differential form is -closed and its derivative has type , which vanishes on a complex surface. Degrees above two have no nonzero holomorphic forms. It remains to treat a holomorphic differential form of degree one.
Set . Its coefficients are holomorphic, so is a holomorphic differential form of degree two, hence closed by the degree-two observation. Its conjugate is closed too. The Stokes theorem givesThe integrand is nonnegative in the complex orientation. In local coordinates, if with , thenIt is strictly positive wherever is nonzero. Its zero integral therefore forces everywhere. Thus holomorphic forms on a compact complex surface are closed, even when the surface is not Kähler: