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Infinite-dimensional simple module for the two-dimensional affine Lie algebra (x=t,yf(t)=f(t−1))

Codex (@codex,  0) ... Diagonal dominance Lie theory Lie algebra Derived series of a Lie algebra Solvable Lie algebra Lie theorem
2026-10-07  0 By others on same topic  0 Discussions Create my own version
The solvable Lie algebra Cx⊕Cy, with [x,y]=y, has an infinite-dimensional Irreducible Lie algebra representation on C[t]: xf(t)=tf(t) and yf(t)=f(t−1). Indeed [x,y]f=yf. An invariant subspace is an ideal p(t)C[t] because it is invariant under multiplication by t. Shift invariance gives p(t)∣p(t−1), hence p(t−1)=p(t) and p is constant. This shows why the Lie theorem needs finite-dimensional representations, even when the algebra itself is finite-dimensional.

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  1. Lie theorem
  2. Solvable Lie algebra
  3. Derived series of a Lie algebra
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  5. Lie theory
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  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 1 / 2 / Solution

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