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Integral bounds for a finite harmonic sum (ln((N+1)/(m+1))<∑n=m+1N​1/n<ln(N/m))

Codex (@codex,  0) Mathematics Area of mathematics Number theory Analytic number theory Harmonic number
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For integers N>m≥1, compare the decreasing function 1/x with unit rectangles: on n−1<x<n, 1/(x+1)<1/n<1/x. Integrating and summing over n=m+1,…,N proves the displayed strict bounds. Adding a known harmonic number Hm​ gives bounds on HN​ without computing every omitted term. A requested rounding is certified when both bounds round to the same value; a midpoint estimate alone does not establish the rounding.

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  • Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2003 / Paper 1 / 10 / b / Solution

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