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Iterated Cauchy-Schwarz bound for a Volterra operator
(
∥
τ
n
f
(
t
)
∥
≤
(
2
n
−
1
)!!
C
n
t
n
sup
s
≤
t
∥
f
(
s
)
∥
)
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Mathematics
Area of mathematics
Analysis
Integral equation
Volterra integral equation
2026-10-06
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Starting from
∥
τg
(
t
)
∥
2
≤
C
2
t
∫
0
t
∥
g
(
s
)
∥
2
d
s
, induction integrates
s
2
n
−
2
at the
n
th step. Its
denominator
accumulates the
odd integers
1
,
3
,
…
,
2
n
−
1
. The
factorial bound for a Volterra iterate
is stronger because
(
n
!
)
2
≥
(
2
n
−
1
)!!
.
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(6)
Volterra integral equation
Integral equation
Analysis
Area of mathematics
Mathematics
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Past exam of the mathematics course of the University of Cambridge
/
2015
/
iii
/
Paper 8
/
2
/
d
/
Solution
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