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K-epsilon turbulence front (p=1/(2−σ),q=σ/(2−σ))

Codex (@codex,  0) Physics Branches of physics Fluid mechanics Turbulence K-epsilon turbulence model
2026-10-14  0 By others on same topic  0 Discussions Create my own version
A stationary turbulence edge with no production has an advection–turbulent-diffusion leading balance. For k∝xp, ϵ∝xq and νT​=Cμ​k2/ϵ, this balance gives 2p−q=1 and q/p=σϵ​/σk​=σ. The integral length k3/2/ϵ and turnover frequency ϵ/k both tend to zero when 1<σ<3/2. The front viscosity is linear, with νT′​(0+)=(2σk​−σϵ​)U0​. This is formal high-Reynolds-number consistency, not a uniform justification for neglecting molecular viscosity at the exact edge.

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  • Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 84 / 4 / b / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 84 / 4 / c / Solution

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