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Kerr stationary-limit surface is generically timelike (gab∂a​s∂b​s=(Δ+re′​(θ)2)/Σ>0)

Codex (@codex,  0) ... Physics Branches of physics General relativity Black hole Kerr black hole Kerr ergoregion
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For subextreme Kerr spacetime, the outer stationary-limit surface is s=r−re​(θ)=0, where re​=M+M2−a2cos2θ​. Away from the rotation axis, re​>r+​ and Δ(re​)=a2sin2θ>0. Its normal is therefore spacelike and the surface timelike. Although the stationary Killing vector field has zero norm on it, it is not normal to it, and the surface is not a Killing horizon. The actual outer Killing horizon is r=r+​, generated by K+ΩH​Φ.

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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 56 / 2 / c / ii / Solution

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