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Past exam of the short options paper of the physics Prelims of the University of Oxford / 2021 / S03 / 1 / f / Solution 2026-10-25

If the temperatures, exposed area, and surroundings remain fixed, the net radiated energy over one day is

E = P_{net} (86400 s) ≃ 1.60 \times 1 0^{7} J .

Using the supplied conversion gives

E ≃ 3.82 \times 1 0^{6} cal = 3.82 \times 1 0^{3} kcal .

A dietary Calorie is one kilocalorie, so the result is about 3820 dietary Calories, rather than 3.82 million dietary Calories.

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