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Linear coefficient bound for normalized univalent functions (∣an​∣≤n(1+1/(n−1))n−1≤ne)

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Complex analysis Univalent function Normalized univalent function
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For f(z)=z+∑n≥2​an​zn in the normalized univalent function class, the integral mean bound for an odd square-root transform gives (2π)−1∫∣f(reiθ)∣dθ≤r/(1−r). The Cauchy integral formula for Taylor coefficients therefore yields ∣an​∣≤r1−n/(1−r). Choosing r=(n−1)/n and applying the logarithm tangent bound gives the displayed bound for every n≥2.

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  • Past exam of the complex analysis: conformal maps and geometry course of the University of Oxford / 2023 / 1 / b / v / Solution

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