Take overdots in this question to mean differentiation with respect to the orbiting particle's proper time . Write , and , with the specific angular momentum. Then the dimensionless timelike effective potential is
The last term is the relativistic correction to the Newtonian centrifugal-plus-gravitational potential. At large the two agree. Newtonian angular momentum gives an infinite inner centrifugal barrier for nonzero ; the relativistic correction lowers that barrier and permits plunge. The exterior problem starts at , where ; extrapolating the potential towards is not a static exterior description.
Circular orbits obey
There are two extrema when : an inner maximum representing an unstable circular orbit and an outer minimum representing a stable one. At equality they merge at ; below it neither exists. More explicitly, evaluate the curvature at a circular orbit:
Timelike circular orbits require . They are radially stable for , so the marginally stable inner limit is . The Newtonian potential instead has one stable minimum at , without an innermost stable circular orbit.
For the Schwarzschild circular-orbit local speed in the question, is the Lorentz factor relative to a local Schwarzschild static observer, not . That observer's clock obeys . Since the particle passes with local speed , . Circular normalization gives
Thus at the innermost stable circular orbit. Using Schwarzschild time in place of the local clock would give a different speed.
For the conserved particle energy measured at infinity, substitute in the circular energy equation. Setting gives
Take the positive root for a future-directed exterior orbit. It approaches at large radius. The marginally bound circular Schwarzschild orbit solves , giving and hence at finite radius. It is unstable; strictly bound circular orbits have , with . The phrase smallest bound orbit here denotes this marginal circular limit, not a prohibition on a bound-energy trajectory plunging below it.
At the innermost stable circular orbit,
A radiatively efficient thin disc with a zero-torque inner boundary condition can therefore release about 5.7% of the accreted rest energy before the plunge. energy advection, stress at the inner edge and photon capture can alter the escaping luminosity, so this is a model efficiency rather than a universal emitted fraction.
For the Kerr ISCO spin limits of an equatorial prograde disc around a rapidly rotating Kerr black hole, the innermost stable circular orbit moves inward and its specific energy decreases. In the ideal extremal limit its Boyer-Lindquist radius tends to , , and the corresponding binding-energy efficiency tends to 42.3%. Retrograde rotation has the opposite trend: the extremal limit is , , giving about 3.8%. The prograde limiting coordinate radius does not identify a massive orbit with the null horizon generator.[ref]
Finally . Dividing by this gives
Its algebraic form is exactly Newtonian, but is the Schwarzschild spacetime areal radius and Schwarzschild time, normalized at infinity. Local clock rates, orbit stability and binding energy remain relativistic. With ,
The marginally bound circular-orbit frequency is about . These Schwarzschild ISCO orbital frequencies and marginally bound frequencies are rotation frequencies per distant stationary observer's time, as intended by using . A static observer at finite radius instead divides both frequencies by , leaving their ratio unchanged. Identifying an observed quasi-periodic oscillation with the innermost stable circular orbit orbital frequency is an additional astrophysical assumption.