Autocovariance of an MA(1) process Created 2026-10-07 Updated 2026-10-14
For the MA(1) , centered white noise gives
Only products of noise values with matching time indices have nonzero expectation. At lag zero there are two squared weights, and ; at lag one there is one shared noise term with weight product ; at higher lags there are none. The calculation needs zero covariance between distinct noise values, not independence. This tridiagonal finite covariance structure makes the finite-sample innovations of an MA(1) process particularly simple.
The lag-one autocorrelation can never exceed in magnitude, since . For , replacing by leaves the entire ACF unchanged. For example and both give ; rescaling the latter noise variance by also matches every autocovariance. Moving-average root reflection explains this ambiguity and why a stable invertibility convention helps identify a representation. Equality of second-order laws need not imply equality of all joint probability distributions unless the processes are Gaussian processes. See Bartlett, lecture 6: equivalent representations and covariance of ARMA processes.
Here the innovation process consists of linear innovations, the linear one-step prediction errors: , where is the closed linear span of the past 's in . For Gaussian processes this is also the conditional expectation prediction error. For general non-Gaussian strong white noise these two notions can differ.
The given is not the linear innovation process. The moving-average factor has its zero at , inside the unit disk, and is noninvertible as a causal moving-average filter. The identity
is the moving-average root reflection that places this zero outside the unit disk. Thus the causal invertible representation has innovation variance , rather than the given variance .
For an explicit verification, define
The filter has constant squared modulus , so is weak white noise with variance . The new moving-average factor has root and is invertible, while its autoregressive factor is causal. Hence the past spans of and agree, and belongs to that past span. Orthogonality of to past therefore identifies it as the linear innovation process. The variance difference proves that it cannot be . If the original noise is Gaussian, the new linear innovations are independent Gaussian variables; without Gaussianity they need only be uncorrelated random variables.