Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 107 4 Solution Created 2026-10-03 Updated 2026-10-05
Use the paper's classical norm convention: is the derivative supremum norm through order two, not an norm. Write and , where the latter is the full Hölder norm of the forcing.
Fix . If the asserted estimate failed, rescaling the functions by their global Hessian matrix Hölder seminorm would produce withIn particular . Choose for whichThe supremum norm of tends to zero, so . Let be the quadratic Taylor polynomial of at , and defineThe domains contain , and vanish at zero. MoreoverThe right side is bounded by and tends to zero locally uniformly. The normalized Hessian matrix bound controls ; integration along line segments then bounds on every compact Euclidean ball. Arzela-Ascoli theorem and a diagonal subsequence argument give convergence in on compact subsets to an entire harmonic function , with and .
After a further subsequence with . The normalization ensures . But each second derivative of is harmonic and has finite global Hölder seminorm with exponent below one. The supplied Liouville theorem makes each derivative constant; it is the globally Hölder case of the polynomial-growth Liouville theorem for harmonic functions. Its value at zero makes it zero, a contradiction. This blow-up compactness proof of an interior Schauder estimate establishes
To absorb the term on the larger Euclidean ball, rescale this estimate to Euclidean balls contained in . For , pairs separated by less than are controlled in a Euclidean ball centred at their first point; farther pairs are controlled directly by . ThusThis is the covering step in the Simon absorption lemma. Take and fix . Iterating makes the remainder tend to zero, since the global seminorm is finite; the error terms form a convergent geometric series. Consequently
For the requested failure of the weaker estimate, take and . The derivative supremum norm and remain bounded, but comparison at and , both in for large , givesThis proves the necessity of Hölder forcing for Schauder estimates. Every member of the sequence is smooth; failure comes from the increasing frequency, not from any lack of individual regularity.