Past exam of the mathematics course of the University of Cambridge 2009 ia Paper 1 7A d Solution Created 2026-09-24 Updated 2026-10-14
There is no such universal constant. For a real parameter , consider the real matrixIts characteristic polynomial is , so both eigenvalues are real and . ButFor any proposed finite , choosing violates the proposed bound. This is an explicit illustration that nonnormal eigenvalues do not bound a quadratic quotient.