At a point in a normal orthonormal frame, torsion-freeness makes the frame brackets vanish there, hence the dual one-forms have zero exterior derivative there. Differentiating the interior product formula then leaves only , the divergence of a Riemannian vector field. Since the point is arbitrary, the identity holds globally.
For fixed , the covariant derivative is linear in its tangent-vector input, so , , is a well-defined linear map. Its trace defines the divergence of a Riemannian vector field. In the given Riemannian orthonormal frame, write . The Levi-Civita connection product rule gives
At , the second sum vanishes by the normal orthonormal frame hypothesis. Thus the th diagonal coefficient of is , and
Equivalently one can take ; the trace does not depend on the orthonormal basis chosen.
Fix any point and use a normal orthonormal frame there. Such frames exist: in geodesic normal coordinates, , and the Christoffel symbols vanish at . Applying the Gram-Schmidt process smoothly to the coordinate fields gives identity coefficients at and zero first derivatives there, so it produces the required frame. Reverse one frame vector if necessary to match the orientation.
Because the Levi-Civita connection is torsion-free, . The supplied formula for the exterior derivative of a one-form gives
Thus , and the graded Leibniz rule implies . Differentiate the formula in part (b):
Since , every summand with vanishes because already occurs in . The remaining term has , so both signs cancel. Hence
The point was arbitrary, proving the global exterior derivative of contracted volume form identity