Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 69 3 Solution Created 2026-10-03 Updated 2026-10-14
For a bound Kepler orbit, the semimajor axis is half the long diameter of the ellipse; if are its apsidal distances, . The orbital eccentricity is , with and semiminor axis . The gravitating centre is a focus, displaced by from the ellipse's geometric centre.
Choose a reference plane, a positive normal and a fixed reference direction in that plane. The ascending node is where the orbit crosses toward positive normal displacement. The longitude of ascending node is the reference-plane angle from the fixed direction to that node. The argument of periapsis is the angle from the ascending node to periapsis, measured in the orbital plane in the direction of motion. The orbital inclination is the angle between the reference normal and the orbital angular-momentum normal, with . The diagram separates the ellipse's shape from these orientation angles.
Size and shape of a Kepler ellipse, and the node, periapsis and inclination angles in a fixed reference frame
. Details. Let and use actions per unit test-particle mass. In the prograde spherical-action chart underlying the stated Hamiltonian, and , so . The radial action then satisfies , consistently with . DefineIf are the old angles, a type-two generating function isDifferentiation with respect to the old angles recovers , and differentiation with respect to the new actions gives the canonical transformationIts triangular integer action matrix has determinant one, so it preserves the angle periodicities. In the new coordinates,These are the Delaunay variables:With the usual choices of angle origins, is mean anomaly, is argument of periapsis, and is longitude of ascending node. The generator rotates the orbit within its plane, whereas rotates that plane about the reference normal; this explains the angular identification. The fast angle obeys Kepler's equation , where is eccentric anomaly.
For retrograde orbits, signed gives and the spherical Hamiltonian uses . The stated plus-sign form is therefore a prograde chart, not a global signed-action formula. The Delaunay variables still use ; on the retrograde branch the generating function is . At , periapsis is undefined, and at or the node is undefined: these are angle-chart degeneracies, not physical singularities.
For the perturbed planet orbit, the radial and vertical frequencies mean small oscillations about a circular equatorial orbit of cylindrical radius . Write and retain the stated quadrupole potential. On the equator,At fixed axial specific angular momentum , the radial effective potential is . Its second derivative at circular balance gives the radial epicyclic frequencyReflection symmetry decouples vertical motion to first order. Expanding the potential in givesso the vertical epicyclic frequency isThe circular orbit is radially stable only for . For in that domain, . Vertical node crossings repeat at frequency while azimuth advances at , so the line of nodes has nodal precession rate . Radial periapsis passages repeat at , giving apsidal precession rate . To leading quadrupole order, with ,This is oblate-quadrupole epicyclic precession. Here denotes the nearly equatorial longitude of periapsis, not alone.
The precession signs above have a small-eccentricity, small-inclination domain. They are not a universal claim for every inclined Kepler ellipse. To see the distinction with the same Delaunay variables, average the perturbation over an unperturbed orbit. Since and , the term linear in integrates to zero and the average in the integral is . ThusDifferentiating at fixed other actions yields the first-order secular ratesTheir nearly equatorial sum reproduces the prograde . For a polar orbit, however, the node is fixed and . This supplies a concrete counterexample to extending the requested forward periapsis precession beyond the intended epicyclic regime.
