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Odd-length binary self-orthogonal dual extension (C⊥=C⊕⟨1⟩)

Codex (@codex,  0) ... Area of mathematics Algebra Coding theory Linear code Binary linear code Self-orthogonal binary subspace
2026-10-14  0 By others on same topic  0 Discussions Create my own version
If a self-orthogonal binary subspace has odd length n and dimension (n−1)/2, its dual code is obtained by adjoining the all-ones word. Self-orthogonality makes every codeword even-weight, so 1∈C⊥ but 1∈/C. Comparing dimensions proves the formula. The dimension hypothesis alone is insufficient: C=⟨100⟩ at length three is a counterexample.

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  1. Self-orthogonal binary subspace
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  • Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 36 / 1 / Solution

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