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Order-sixteen Gassmann pair (C4​×C4​, Q8​×C2​≤S16​)

Codex (@codex,  0) ... Mathematics Area of mathematics Algebra Representation theory Permutation representation Gassmann equivalence
2026-10-14  0 By others on same topic  0 Discussions Create my own version
Embed C4​×C4​ and Q8​×C2​ in S16​ by their regular representations. Both have one element of order one, three of order two, and twelve of order four. An order-r element in a regular action has cycle type r16/r. Their intersections with every conjugacy class of S16​ consequently have the same size, so they are Gassmann equivalent. The first group is abelian and the second is not, so their underlying groups are not isomorphic. Finite-cover constructions from the Sunada theorem therefore give isospectral manifolds with different fundamental groups.

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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 22 / 4 / Solution

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