Past exam of the computer science course of the University of Oxford / 2020 / Artificial intelligence / 3 / g / Solution

Consider a B-node whose parent is an A-node with an already completed incumbent outcome having A-coordinate $\alpha$. At the B-node, let $(x,y)$ be the best completed child pair found so far according to B's coordinate. Every remaining child can be skipped, and this B-option discarded by its parent, ifUse a strict inequality if ties must remain open; equality is safe under the fixed rule that the parent retains its already selected child on an A-coordinate tie. This is a nearly-zero-sum pruning rule.

To prove it, note first that a completed max-n search value is some terminal utility pair: each backup copies one entire child pair. Thus the nearly-zero-sum inequality holds at every completed subtree, not just at leaves. Since B maximizes its own coordinate, the ultimately selected pair $(u,v)$ at this B-node has $v\ge y$. ThereforeThe already available A-option is at least as good, so remaining children of this B-node cannot alter the parent's selected continuation under the stated tie rule. The second half of the two-sided nearly-zero-sum condition also gives $x+y\ge -ϵ$, henceConsequently $x+2ϵ\le \alpha$ is another sufficient cutoff, useful if one phrases the test using the observed A-coordinate. The pair-based test is sharper: the value of $y$ can certify a cutoff even when the conservative $x+2ϵ$ test cannot.

When $ϵ=0$, every pair satisfies $y=-x$, and the rule reduces to $x\le \alpha$, the ordinary MIN-node alpha-beta pruning cutoff. The extra $2ϵ$ in the A-coordinate-only condition is necessary in general: an observed pair $(-1,0)$ satisfies the bound for $ϵ=1$, but B prefers an unseen $(1-\delta ,\delta )$ for $0<\delta <1$. A increases by almost $2ϵ$; using just $x+ϵ$ as the upper bound would be invalid.

Implementation must discard the ruled-out B-option at its parent rather than return $(x,y)$ as an exact completed utility pair. The proof uses an actual completed alternative at that parent; it does not authorize passing arbitrary distant ancestor bounds through general-sum game backups as if every scalar alpha-beta pruning invariant still held. With these local certified cutoffs, an induction over completed subtrees preserves the selected pair and hence the root outcome.