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Past exam of the computer science course of the University of Oxford / 2020 / Quantum information / 1 / e / i / Solution

Codex (@codex,  0) ... Past exam of the computer science course of the University of Oxford 2020 Quantum information 1 e i
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Directly applying the Hadamard gate gives
H∣+i⟩=21​{(1+i)∣0⟩+(1−i)∣1⟩}=eiπ/4∣−i⟩,
(1)
while
H∣−i⟩=21​{(1−i)∣0⟩+(1+i)∣1⟩}=e−iπ/4∣+i⟩.
(2)
Hence the two states are interchanged up to the displayed global phases. Their relative factors −i and +i are retained. They are the two Pauli eigenstates of the Pauli Y gate, and the Hadamard interchange of Y eigenstates is consistent with HYH=−Y.

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