Past exam of the computer science course of the University of Oxford / 2023 / Combinatorial optimisation / 3 / d / iii / Solution

Use minimum-weight edge cover by matching savings. Reject inputs with an isolated vertex. For every vertex $v$, choose a cheapest incident edge $e_v$ and write $c_v=w(e_v)$. Define a baseline and a saving for each edge $uv$ byCompute a maximum-weight matching $M$ using $p$ as its weights, allowing the empty matching in a graph and imposing no maximum-cardinality condition. Negative savings may be ignored. ReturnThis is an edge cover. Since original weights are nonnegative, removing duplicate appearances of an edge cannot increase the total, and henceTo prove optimality, take a minimum-weight edge cover and remove redundant edges until it is inclusion-minimal. Nonnegative weights ensure that its weight does not increase, so it remains optimal. As proved in (i), its components are star graphs. Choose one edge from each star graph, forming a matching in a graph $N$.

In a star graph with center $a$, selected leaf $b$, and other leaves $L$, this choice contributes $w(ab)+{\sum }_{v\in L}{c}_v$ to $B-p(N)$. Each other leaf $v$ has its edge $av$ available, so $c_v\le w(av)$. Thus this contribution is at most the weight of that star graph. Summing over components yieldsSince $M$ maximizes saving, $p(M)\ge p(N)$, and consequentlyAll inequalities are equalities. Therefore $F_M$ is a minimum-weight edge cover. This proof also handles zero weights and duplicate cheapest-edge choices.

Finding all $c_v$ and constructing $F_M$ takes $O(|V|+|E|)$ time. A general-graph maximum-weight matching polynomial-time algorithm supplies the only substantial step; the documented routine runs in $O(|V{|}^3)$ arithmetic time. Exact rational or integer weights avoid floating-point comparisons affecting optimality.^[ref]