For a positive integer , the chromatic polynomial counts proper vertex colorings from a palette of labelled colors, where adjacent vertices must have different colors. The counting function agrees with a polynomial, as proved by deletion-contraction in the next part.
For an edge , colorings of divide into those giving different colors, counted by , and those giving them the same color, counted by . Parallel edges produced by contraction may be suppressed. Thus
For an edgeless graph on vertices, . Induct on the number of edges, allowing smaller vertex counts for contractions. If both smaller expansions have alternating nonnegative coefficients, the contraction's leading degree is one lower, so subtracting it gives
with absent coefficients interpreted as zero. Each coefficient remains nonnegative. Both terms have zero constant coefficient for nonempty graphs, so the resulting expansion is
This induction simultaneously proves the counting function is a polynomial.
For a triangle, . For , deleting an edge leaves a path with polynomial , and contracting it leaves . Deletion-contraction and induction give
The path formula chooses its first color freely and each succeeding color in ways.
Choose the central vertex's color in ways. Every rim vertex must avoid that color, so the rim is a cycle colored using the remaining colors. Hence

Articles by others on the same topic (0)

There are currently no matching articles.