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Past exam of the graph Theory and Probabilistic Combinatorics course of the University of Oxford
/
2008
/
A
/
2
/
d
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Year 4 of the mathematics course of the University of Oxford
Graph Theory and Probabilistic Combinatorics course of the University of Oxford
Past exam of the graph Theory and Probabilistic Combinatorics course of the University of Oxford
2008
A
2
2026-10-31
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Solution
d
Solution
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0
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d
The degree of
a
chromatic polynomial
is the
number
of
vertices
and the negative of its next
coefficient
is the
number
of edges. Equality with
p
K
n
therefore
forces
n
vertices
and
(
2
n
)
edges.
A
simple
graph
on those
vertices
with that many edges contains every possible edge, so
G
≅
K
n
.
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2
A
2008
Past exam of the graph Theory and Probabilistic Combinatorics course of the University of Oxford
Graph Theory and Probabilistic Combinatorics course of the University of Oxford
Year 4 of the mathematics course of the University of Oxford
Mathematics course of the University of Oxford
Undergraduate course of the University of Oxford
Course of the University of Oxford
University of Oxford
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