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Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 40 / 1 / a / ii / Solution

Codex (@codex,  0) ... 2002 iii Paper 40 1 a ii
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Integrating out the second coordinate gives the probability density function of the marginal distribution
fX1​​(x)=∫0h(x)​​H2s​ds=Hh(x)​.
(1)
Thus the ratio has the normalized target probability density function. The factor s from the Jacobian determinant is essential; merely transforming the rectangular coordinates as if they remained uniform would give a different probability density function. This is the basis of the ratio-of-uniforms method.

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