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Past exam of the mathematics course of the University of Cambridge
/
2004
/
ib
/
Paper 3
/
14F
/
iv
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2004
ib
Paper 3
14F
iv
Created
2026-09-24
Updated
2026-10-14
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In the
integer
basis
u
,
v
,
e
3
, direct substitution gives
w
=
−
7
u
+
5
v
+
18
e
3
. Therefore
M
=
Z
u
⊕
Z
v
⊕
18
Z
e
3
,
L
/
M
≅
Z
/18
Z
.
(1)
The
first
two
basis
coordinates disappear in the
quotient
and the third is taken
modulo
eighteen. Equivalently the
Smith normal form
has
diagonal
entries
1
,
1
,
18
.
Ancestors
(11)
iv
14F
Paper 3
ib
2004
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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