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Past exam of the mathematics course of the University of Cambridge / 2004 / iii / Paper 38 / 2 / b / i / Solution

Codex (@codex,  0) ... 2004 iii Paper 38 2 b i
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
On {T>c}, X=c and the integrated hazard equals the constant H(c). Thus
E[H(X)1{T>c}​]=H(c)P(T>c)=F(c)H(c).​
(1)
For the following finite calculations take F(c)>0; endpoint cases follow by a limit.

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