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Past exam of the mathematics course of the University of Cambridge / 2008 / ia / Paper 4 / 6D / c / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2008 ia Paper 4 6D c
Created 2026-09-24 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
The greatest common divisor is
gcd(437,1012)=gcd(19⋅23,44⋅23)=23,
(1)
since 19 and 44 are coprime integers. Part (b) therefore gives 1012/23=44​ distinct 437th powers in the nonzero multiplicative group of a finite field F1013×​. If “powers mod 1013” includes all residue classes, the additional value 0=0437 gives 45​ values including zero. The distinction is relevant because part (b) explicitly works in the nonzero group.

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