The assertion is true. The assumed finite multiplicity means that is not identically zero and has an isolated zero of order at . Choose so that and has no other zeros in this closed disc. On its boundary,The joint holomorphy established above gives uniformly on that circle as . For sufficiently small , therefore, . By Rouché's theorem, has exactly zeros in , counted with multiplicity. In particular it has at least one zero in . This preserves the total local zero count, without asserting that the zeros remain together.
Articles by others on the same topic
There are currently no matching articles.