Choose a Weierstrass equation of an elliptic curve, with origin at infinity. For , draw their chord, or the tangent if they coincide, and call its third intersection , counted with intersection multiplicity. The line through and gives a third point ; define . This is the chord-and-tangent group law. The inverse of an affine point on is , obtained from its vertical line through . These conventions give identity , and cover tangent and flex cases by multiplicity.
Here is a proof of associativity, without assuming that the geometric construction already defines a group. Work first over an algebraic closure and use divisors on an algebraic curve. The Riemann-Roch theorem says . For a smooth genus-one curve the canonical divisor has degree zero, so every degree-one divisor has . Thus every divisor class of degree one has a unique effective representative, necessarily a single point. Existence follows from a nonzero section; uniqueness follows because two distinct effective representatives would give linearly independent sections in the same one-dimensional space. Consequently
is a bijection: add to any degree-zero divisor class, and use its unique degree-one representative.
A line through cuts out a divisor linearly equivalent to , since the line at infinity has triple intersection at the Weierstrass flex . Equivalently, the ratio of the line equation to that of the line at infinity has principal divisor . Thus the three corresponding degree-zero classes sum to zero. Applying the same fact to shows that the point produced by the chord-and-tangent process satisfies
Addition of divisors modulo principal divisors is associative. The two parenthesizations of therefore have identical classes; injectivity of the displayed bijection makes them the same point. Hence the chord-and-tangent law is associative. This is associativity of the chord-and-tangent law via divisor classes. Its construction is defined over the original field, so the same conclusion holds for its rational points.

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