In cotangent bundle coordinates , the Liouville one-form and the canonical symplectic form are
The twisted cotangent symplectic form is closed: pullback of a differential form commutes with the exterior derivative, so
To prove the form is nondegenerate, write a tangent vector in these coordinates as and test its pairing with an arbitrary vertical vector . The base differential two-form has zero pairing with vertical vectors, hence
A vector in the kernel of a linear map therefore has . Pairing it next with every gives , so . Thus the kernel is zero at every point, independently of the size or rank of . Together with closedness, this proves is a symplectic form. The argument is local only for convenience; the nondegenerate property is intrinsic and the coordinate charts cover the whole cotangent bundle.

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