Assume and . For , use the method of multiple scales with and complex amplitudesAt first order the forcing equations areThe product has frequencies . Its coefficient is , while it has no coefficient. Removing the secular terms givesThe leading initial conditions give and . Put , . The primary parametric resonance of a two-to-one oscillator pair is governed byFor , choose . Solving with yieldsIf , let ; replace by and by . On the boundary , take the continuous limit:Thus exponential growth occurs when and , on the scale . Equality is a marginal case that can produce linear slow growth: for the displayed initial phase excites it, whereas for it does not. If , stays identically zero and the other oscillator is exactly uncoupled. The leading amplitude is constant; its backreaction is a higher-order effect on this time scale.
These are leading approximations for bounded slow time , hence , while the amplitudes stay . First-order corrections can enforce the initial velocities exactly; the leading formula alone has an initial-velocity mismatch. In the unstable case the expansion must not be extrapolated through arbitrarily large amplification, where weak coupling and omitted terms cease to be uniform.
For , both leading oscillations have frequencies , so their quadratic product contains only frequencies . There is no first-order resonant coupling: the solvability condition in the method of multiple scales gives and , a frequency shift without first-order amplitude growth. The constant and second-harmonic corrections can feed back into the fundamental at second order. Consequently the first possible growth scale from this second-order resonance from quadratic oscillator coupling isThis identifies the possible slow scale, not a guaranteed instability for every parameter or initial state. In particular, the first-order frequency shift may detune the second-order resonance unless appropriately tuned; a second-order amplitude analysis would decide actual growth.
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