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Past exam of the mathematics course of the University of Cambridge / 2015 / ii / Paper 2 / 33C / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2015 ii Paper 2 33C b
Created 2026-09-24 Updated 2026-10-06  0 By others on same topic  0 Discussions Create my own version
The photon number in thermal blackbody radiation is not fixed, so μ=0. With x=E/(kB​T),
U=AV(kB​T)4∫0∞​ex−1x3​dx=AV(kB​T)415π4​.
(1)
The integral is a temperature-independent finite constant (its explicit value follows from the gamma-zeta integral). Differentiating at fixed volume gives
CV​=154π4​AVkB4​T3,α=3.​
(2)

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