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Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 22 / 6 / c / ii / Solution

Codex (@codex,  0) ... 2015 iii Paper 22 6 c ii
Created 2026-10-03 Updated 2026-10-06  0 By others on same topic  0 Discussions Create my own version
Assume Tη=ηT, and let (A,a) be an algebra for a monad. Its unit identity gives aηA​=1A​. Naturality of η at a:TA→A, followed by the assumed equality, gives
ηA​a=TaηTA​=TaTηA​=T(aηA​)=1TA​.
(1)
Thus every algebra action is invertible, with its inverse prescribed by the unit:
a−1=ηA​.​
(2)

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