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Past exam of the mathematics course of the University of Cambridge / 2018 / ii / Paper 2 / 21H / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 21H a
Created 2026-09-24 Updated 2026-10-03  0 By others on same topic  0 Discussions Create my own version
For every nonempty simplex σ of K, let bσ​ be its barycentre. The first barycentric subdivision K′ has the bσ​ as vertices, and
[bσ0​​,…,bσq​​]
(1)
is a simplex exactly when, after reordering, σ0​⊊⋯⊊σq​. Its realization is the same polyhedron as that of K. The iterated barycentric subdivision is defined by
K(0)=K,K(r+1)=(K(r))′.​
(2)

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