For this Adams–Moulton method, the characteristic polynomials of a linear multistep method are
Expansion at zero gives
Part (a) therefore shows that the method has order exactly three.
It is consistent because its order is at least one. The roots of are and ; both lie in the closed unit disk, and the only unit-modulus root is simple. Thus the method is zero-stable. By the Dahlquist equivalence theorem, consistency and zero stability imply convergence. Hence the method is

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