Given , choose a sequence with , which is possible by part (a). The bound gives
so is a Cauchy sequence. Since is a Banach space, it converges. Define
The same estimate shows that this limit does not depend on the approximating sequence. Passing to the limit proves linearity and
so . It agrees with on . If two bounded extensions existed, their difference would vanish on the dense subspace and, by continuity, on its closure . Thus the extension is unique. This is the extension of a bounded linear operator from a dense subspace.

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