Given , choose a sequence with , which is possible by part (a). The bound givesso is a Cauchy sequence. Since is a Banach space, it converges. DefineThe same estimate shows that this limit does not depend on the approximating sequence. Passing to the limit proves linearity andso . It agrees with on . If two bounded extensions existed, their difference would vanish on the dense subspace and, by continuity, on its closure . Thus the extension is unique. This is the extension of a bounded linear operator from a dense subspace.
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