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Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 3 / 22H / d / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 3 22H d
Created 2026-09-24 Updated 2026-10-03  0 By others on same topic  0 Discussions Create my own version
No. In the Lebesgue space L1([0,2π]), let
fn​(t)=sin(nt).
(1)
For every g∈L∞([0,2π]), finiteness of the interval gives g∈L1([0,2π]), and the Riemann-Lebesgue lemma yields
∫02π​fn​(t)g(t)dt⟶0.
(2)
The duality of Lp spaces therefore shows that fn​⇀0 in L1. On the other hand,
∥fn​∥1​=∫02π​∣sin(nt)∣dt=4
(3)
for every n. Thus weak convergence does not imply norm convergence in this L1 space; the Weakly null sine sequence in L1 is the required counterexample.

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