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Past exam of the mathematics course of the University of Cambridge / 2019 / iii / Paper 113 / 4 / c / i / Solution

Codex (@codex,  0) ... 2019 iii Paper 113 4 c i
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For the closed immersion i:Y↪X, the ideal sheaf of a closed subscheme gives
0⟶IY/X​⟶OX​⟶i∗​OY​⟶0.
(1)
Because the projective hypersurface is cut out by one homogeneous polynomial f of degree d, multiplication by f identifies
IY/X​≅OX​(−d)=OX​(1)⊗(−d).​
(2)
This is the ideal-sheaf sequence of a projective hypersurface.

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