The truncated Perron formula says that, for and ,
where an endpoint has half weight and the error is controlled by
Apply this with , , and
Part (b) makes the integrand . Move the contour to
using a contour that stays inside the Zero-free region of the Riemann zeta function near small . The estimates supplied in the question give on the new contour. Its vertical segment is therefore
after decreasing . The horizontal segments and the Perron truncation error are
No residue is crossed because has a zero, rather than a pole, at . Thus the Mertens function satisfies
for some absolute .

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