Insert the mode expansion of a free field into the classical expression for . The and terms cancel after , while the mixed terms give, after the stated normal ordering,Thus the momentum operator counts each occupied mode with weight .
The vacuum has zero momentum and is invariant under translations. HenceThus a one-particle momentum eigenstate remains the same ray and acquires the translation phase appropriate to its momentum.
Similarly . Transforming both terms of the field expansion givesTherefore the spatial translation operator generated by translates the field argument. Equivalently, its action on states translates a wavefunction in the opposite argument convention.
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