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Past exam of the mathematics course of the University of Cambridge
/
2021
/
ia
/
Paper 3
/
11B
(Vector Calculus)
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Course of the University of Cambridge
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2021
ia
Paper 3
Created
2026-09-24
Updated
2026-09-24
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Table of contents
a
11B
Solution
a
b
11B
Solution
b
c
11B
Solution
c
a
0
0
0
11B
Solution
0
0
0
a
Set
x
=
a
u
,
y
=
b
v
,
z
=
c
w
.
(1)
The
ellipsoid
becomes the unit ball and the
Jacobian determinant
is
ab
c
. Therefore
Vol
=
ab
c
Vol
(
B
1
)
=
3
4
πab
c
,
(2)
assuming
a
,
b
,
c
>
0
.
b
0
0
0
11B
Solution
0
0
0
b
Fix the
first
index
i
and form the
vector field
with components
F
j
=
T
ij
. The
divergence theorem
gives
∫
S
F
j
n
j
d
S
=
∫
V
∂
j
F
j
d
V
.
(1)
Substitution yields the
tensor divergence theorem
∫
S
T
ij
n
j
d
S
=
∫
V
∂
x
j
∂
T
ij
d
V
.
(2)
c
0
0
0
11B
Solution
0
0
0
c
For
u
=
(
−
y
,
x
,
α
)
, one has
∇
⋅
u
=
0
, and therefore
a
i
=
∂
j
(
u
i
u
j
)
=
(
u
⋅
∇
)
u
i
=
(
−
x
,
−
y
,
0
)
i
.
(1)
Close the upper half-
ellipsoid
with its
unit-disk
base
D
in the
plane
z
=
0
. By
symmetry
,
∫
V
(
−
x
,
−
y
,
0
)
d
V
=
0.
(2)
On the base, the outward normal is
n
=
(
0
,
0
,
−
1
)
, so
u
i
u
j
n
j
=
−
α
u
i
=
(
α
y
,
−
αx
,
−
α
2
)
i
.
(3)
The
first
two components integrate to zero over the disk, while the third integrates to
−
π
α
2
. The closed-
surface
tensor
identity therefore gives
∫
S
u
i
u
j
n
j
d
S
=
(
0
,
0
,
π
α
2
)
i
.
(4)
Multiplying by
β
2
,
F
=
(
0
,
0
,
π
α
2
β
2
)
.
(5)
Ancestors
(9)
Paper 3
ia
2021
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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