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Past exam of the mathematics course of the University of Cambridge
/
2021
/
ia
/
Paper 4
/
1E
/
iii
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Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2021
ia
Paper 4
1E
Created
2026-09-24
Updated
2026-09-24
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Solution
iii
Solution
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iii
This can fail in the same example
as
in part (
i)
:
g
∘
f
is injective on the singleton
X
, but
g
(
a
)
=
g
(
b
)
.
For the final count,
g
∘
f
=
id
X
forces
f
to be injective. There are
n
(
n
−
1
)
⋯
(
n
−
m
+
1
)
=
(
n
−
m
)!
n
!
(1)
such
functions
f
. Once
f
is chosen,
g
is forced on the
m
elements of
f
(
X
)
and has
m
independent
choices
at each of the other
n
−
m
elements of
Y
. Hence the
number
of
pairs
is
(
n
−
m
)!
n
!
m
n
−
m
.
(2)
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1E
Paper 4
ia
2021
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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