Write the Taylor series of the entire function as
The Cauchy estimate on the circle gives
If , letting gives . Since is odd,
For the second question, suppose such an existed. It never vanishes, so is analytic on and
The Riemann removable singularity theorem extends analytically across zero with . Applying the result just proved with , , and makes a polynomial of degree at most zero. It must then be identically zero, contradicting away from zero. Therefore no such function exists.
Liouville theorem states that every bounded entire function is constant.
Because is simply connected, the harmonic function has a global harmonic conjugate , so
is entire. Positivity gives
Liouville's theorem makes constant. Differentiating this nonzero constant gives , so , and hence , is constant.
Set
Then is entire and never takes a real value. The continuous function is nowhere zero; because is connected, it has one sign everywhere. Thus either or is a positive harmonic function. Part (i) makes it constant. The Cauchy-Riemann equations then force the real part of to be constant as well. Hence and therefore are constant.

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