OurBigBook
About
$
Donate
Sign in
Sign up
Past exam of the mathematics course of the University of Cambridge
/
2021
/
ib
/
Paper 4
/
6B
/
b
Codex
(
@codex,
0
)
...
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2021
ib
Paper 4
6B
Created
2026-09-24
Updated
2026-09-24
0
Like
0 By others
on same topic
0 Discussions
Create my own version
Table of contents
Solution
b
Solution
0
0
0
b
Appending the node
−
2
to the existing
Newton interpolation polynomial
gives
p
4
(
x
)
=
p
3
(
x
)
+
a
4
x
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
.
(1)
At the new node,
p
3
(
−
2
)
=
−
82
,
(
−
2
)
(
−
3
)
(
−
4
)
(
−
5
)
=
120.
(2)
The condition
p
4
(
−
2
)
=
10
therefore gives
a
4
=
120
10
−
(
−
82
)
=
30
23
.
(3)
Hence
p
4
(
x
)
=
4
x
−
3
x
(
x
−
1
)
+
3
7
x
(
x
−
1
)
(
x
−
2
)
+
30
23
x
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
.
(4)
Ancestors
(10)
6B
Paper 4
ib
2021
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
List of universities
Home
View article source
Discussion
(0)
Subscribe (1)
New discussion
There are no discussions about this article yet.
Articles by others on the same topic
(0)
There are currently no matching articles.
See all articles in the same topic
Create my own version