True. Continuity and compactness give a maximum of on . At an interior maximum the Hessian matrix is negative semidefinite, so its trace satisfies , contradicting . The maximum must therefore occur on . This is the strict form of the maximum principle for subharmonic functions.
False. On the open unit disk, let
Then , but the unique maximum is , whereas on the boundary.
False. On the open unit disk take, for ,
Its relevant fourth derivatives satisfy
Nevertheless, since , every point with has
Thus the maximum lies strictly inside .
True. This follows from the maximum principle for harmonic functions. A direct reduction to part (i) is also possible: for , set
Then , so
Because is bounded, uniformly as . Taking the limit yields

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