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Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 201 / 5 / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 201 5 b
2026-09-28  0 By others on same topic  0 Discussions Create my own version
By the strong law of large numbers,
nTn​​⟶σ2
(1)
almost surely. Brownian scaling and a maximal inequality show that changing Brownian time by o(n) changes its value by oP​(n​); explicitly, first restrict to ∣Tn​−nσ2∣≤δn, bound the Brownian maximum over a time interval of length 2δn, and then let δ↓0. Consequently
n​BTn​​−Bnσ2​​⟶0
(2)
in probability.
But
n​Bnσ2​​∼N(0,σ2)
(3)
for every n. Since BTn​​ has the law of Sn​, Slutsky theorem proves the Central limit theorem from the Skorokhod embedding:
n​Sn​​ d​ N(0,σ2)​.
(4)

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