Past exam of the mathematics course of the University of Cambridge / 2022 / ib / Paper 3 / 4D / Solution

At a regular constrained stationary point of $F$ on $G=0$, the Lagrange multiplier method solvesFor the first problem, substitute $z=1+xy$ to obtainIts stationary equations imply either $x=y$ or $xy=0$, and in either case the only real stationary point is $x=y=0$, $z=1$. Coercivity ensures that the minimum is attained, soat $(0,0,1)$.

For the second problem, the arithmetic-geometric mean inequality givesConsequentlyEquality occurs at $(0,0,1)$, and hence