The periodic Wirtinger inequality says that if is continuously differentiable, -periodic, and has mean zero, thenEquality holds exactly for a linear combination of and .
First suppose is one positively oriented simple closed curve, parametrized by arc length as for . Translating the origin, which changes neither length nor area, makes both and have mean zero. Green theorem and the Cauchy-Schwarz inequality giveApplying Wirtinger's inequality to both coordinate functions and using the unit-speed identity yieldsand therefore the planar isoperimetric inequalityFor several boundary components, apply the simple-curve result to the relevant enclosed regions and use ; holes only decrease the area.
Equality in both inequalities forcesfor constant vectors , with the unit-speed and Cauchy-Schwarz equality conditions making and perpendicular and equally long. Thus the boundary is a circle. Conversely, a circular domain has area and perimeter , so equality holds.
Let and be opposite interior angles of a convex quadrilateral with side lengths , and let . The Bretschneider formula gives its area asThe fixed side lengths fix the first term, while the second term is nonpositive. Hencewith equality exactly when . Opposite angles are supplementary exactly when the quadrilateral is a cyclic quadrilateral. The given is cyclic, so it attains this upper bound andA crossed or concave competitor can be uncrossed or reflected across a diagonal without changing its side lengths and without decreasing its unsigned area, so the same bound applies. Apart from degenerate coincidences, equality holds precisely when is also cyclic with the stated cyclic ordering of its side lengths.
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