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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 105 / 2 / b

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 105 2
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b
If the asserted Poincaré inequality failed, after rescaling there would be uj​∈H with
∥uj​∥2​=1,∥Duj​∥2​⟶0.
(1)
The sequence is bounded in H1(U). By the Rellich-Kondrachov compactness theorem, a subsequence converges strongly in L2(U) to some u and weakly in H1(U). Its weak gradient is zero, so connectedness of U makes u almost everywhere constant. Continuity of the integral under L2 convergence gives ∫U​u=0, hence u=0. Strong convergence would then imply ∥uj​∥2​→0, contradicting the normalization. Therefore the required constant exists.

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