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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 211
/
6
/
c
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Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2022
iii
Paper 211
6
2026-09-28
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Solution
c
Solution
0
0
0
c
Let
τ
=
T
−
t
and
set
V
(
t
,
z
)
=
exp
{
P
(
τ
)
+
Q
(
τ
)
z
+
R
(
τ
)
z
2
}
.
(1)
Then
V
V
z
=
Q
+
2
R
z
,
V
V
zz
=
2
R
+
(
Q
+
2
R
z
)
2
,
V
V
t
=
−
(
P
˙
+
Q
˙
z
+
R
˙
z
2
)
.
(2)
For
B
(
z
)
=
a
−
b
z
and
C
(
z
)
=
c
, matching constant, linear, and quadratic
coefficients
gives
R
˙
=
2
c
2
R
2
+
2
(
θρ
c
−
b
)
R
+
2
1
θ
(
θ
−
1
)
,
(3)
Q
˙
=
2
a
R
+
(
θρ
c
−
b
)
Q
+
2
c
2
QR
,
(4)
and
P
˙
=
a
Q
+
c
2
R
+
2
1
c
2
Q
2
.
(5)
The terminal condition becomes
P
(
0
)
=
Q
(
0
)
=
R
(
0
)
=
0
. The
first
equation
is
a
Riccati equation
; once it is solved, the
second
is linear in
Q
, followed by direct integration for
P
.
Ancestors
(10)
6
Paper 211
iii
2022
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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